The most general solution of tan theta -1
WebOct 13, 2024 · The most general solution of `tan theta =-1 and cos theta = 1/sqrt 2 ` is : Doubtnut 2.49M subscribers Subscribe 4.4K views 4 years ago To ask Unlimited Maths doubts download Doubtnut from... WebFeb 10, 2024 · #3 tan^2 theta = 1 or tan^2 theta = 1/3 or tan theta = +- 1/sqrt 3, tan theta = 1/sqrt 3 ; tan (pi/6) = 1/sqrt 3 ; tan (pi +pi/6) = 1/sqrt 3 :. theta = (pi/6) , theta ...
The most general solution of tan theta -1
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WebSolve for ? tan (theta)=1. tan (θ) = 1 tan ( θ) = 1. Take the inverse tangent of both sides of the equation to extract θ θ from inside the tangent. θ = arctan(1) θ = arctan ( 1) Simplify the right side. Tap for more steps... θ = π 4 θ = π 4. The tangent function is positive in the first and third quadrants. To find the second solution ... WebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.
WebApr 12, 2024 · If `sintheta= - 1/2` and `tan theta = 1/sqrt(3)` then the most general values of `theta` equal to (A) `2npi+pi/6` (B) `2npi=(5pi)/6` (C) `2npi+(7pi)/6` (D) n... If `sintheta= - 1/2`... WebThe most general solution of tanθ=−1,cosθ=1/2 is- A nπ+7π/4 B nπ+(−1) n7π/4 C 2nπ+7π/4 D None of these Medium Solution Verified by Toppr Correct option is C) Given tanθ=−1 tanθ=−tan 4π tanθ=tan(π− 4π)ortanθ=tan(2π− 4π) ⇒tanθ=tan 43π or tanθ=tan 47π ⇒θ=nπ+α where α= 43πor 47π Also, given cosθ=1/2 cosθ=cos 4πorcosθ=cos(2π− 4π)
WebJan 3, 2024 · Step 1: Rewrite the equation in terms of one function of one angle. Step 2: Solve for values in the trigonometric function. Step 3: List the various possible solutions for the angle. Solve for the angle. Step 4: Solve for the variable, if necessary. Step 5: Apply any restrictions, if available. WebNov 20, 2016 · Explanation: tanθ +1 = 0 # :. tan theta = -1 ; tan (pi-45)= -1. and tan(2π− 45) = −1 ∴ θ = π −45 = 1350 and θ = 2π −45 = 360 − 45 = 3150. Solution: θ = 1350 and θ = 3150 [ans]
WebT =b / lambda_max = 3e-3 mK / (600e-9 m) = 1/200e-6 K = 0.5e4 K = 5000 K. Problem 8: The Sun’s photosphere has a temperature of ∼ 5,800 K. After several billion years, the Sun will evolve into a red giant star and finally into a white dwarf star. As a white dwarf, the Sun will have a photospheric temperature of ∼ 20,000K and a size comparable to the size of the …
WebOriginally Answered: What is the most general value of theta that satisfies both the equations: cos theta=-1/√2 & tan theta=-1? Theta will be 45° here. Put theta =45° or π/4 Which will give the same answers Doug Dillon PhD, Mathematics from Queen's University at Kingston Author has 10.1K answers and 8.6M answer views 8 mo Related chris godwin coloring pageWebtan θ = 1 = tan π 4, tan π + π 4. θ = π 4, 5 π 4. The value of θ between 0 and 2 π which satisfies both the equations is 5 π 4. General value is 2 n π + 5 π 4 = 2 n + 1 π + π 4. Hence, the most general solution is tan θ = 1 and cos t h e t a = - 1 2 is 2 n π + 5 π 4 = 2 n + 1 π + π 4. Suggest Corrections. 0. chris godwin fantasy dataWebGeneral Solution of Trigonometric Equation (a) If sin θ = 0, then θ = n π, n ∈ I (set of integers) (b) If cos θ = 0, then θ = (2n+1) π 2, n ∈ I (c) If tan θ = 0, then θ = n π, n ∈ I (d) If cot θ = 0, then θ = (2n+1) π 2, n ∈ I Note : Since sec θ ≥ 1 or sec θ ≤ 1, therefore sec θ = 0 does not have any solution. gentry beach emailWebMar 29, 2024 · Transcript. Example 19 Find the principal solutions of the equation tan x = – 1/√3 . tan x = – 1/√3 We know that tan 30° = 1/√3 Since tan x is negative So, x will lie in llnd and lVth Quadrant Value in llnd Quadrant = 180 – 30° Value in lVth Quadrant = 360 – 30° So Principal Solutions are x = 150° x = 150/180 π x = 𝟓/𝟔 ... gentry beach net worthWebTrigonometric equation is an equation involving one or more trigonometric ratios of unknown angles. It is expressed as ratios of sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), cosecant (cosec) angles. For example, cos 2 x + 5 sin x = 0 is a trigonometric equation. chris godwin fantasy footballWebA launch angle of 45 degrees displaces the projectile the farthest horizontally. This is due to the nature of right triangles. Additionally, from the equation for the range : We can see that the range will be maximum when the value of is the highest (i.e. when it is equal to 1). Clearly, has to be 90 degrees. gentry beach familyWebIn celestial mechanics, a Kepler orbit (or Keplerian orbit, named after the German astronomer Johannes Kepler) is the motion of one body relative to another, as an ellipse, parabola, or hyperbola, which forms a two-dimensional orbital plane in three-dimensional space. A Kepler orbit can also form a straight line.It considers only the point-like … gentry beach lawsuit